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1.25x^2-4x-58=0
a = 1.25; b = -4; c = -58;
Δ = b2-4ac
Δ = -42-4·1.25·(-58)
Δ = 306
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{306}=\sqrt{9*34}=\sqrt{9}*\sqrt{34}=3\sqrt{34}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-3\sqrt{34}}{2*1.25}=\frac{4-3\sqrt{34}}{2.5} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+3\sqrt{34}}{2*1.25}=\frac{4+3\sqrt{34}}{2.5} $
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